Don't Mess With WMM!

@birddogthecat - I think in this case you might have meant “Oops I did it again.” There’s a rich vein of this material in Gordon’s collection, that’s why he’s keeping the thread open. >:)



doo di doo di doo…wake me up, before you go-go…

… ubi loqui debuit ac potuit :smiley:

@alekz “Have Gun, Will Travel.” Wasn’t “ubi loqui debuit ac potuit” on Paladin’s business card? I was an avid watcher of the show.



OMG…are we now going to have a Paladin - Have Gun Will Travel thread?

“A knight without armour in a savage land”

res ipsa loquitur

Attached files

FAB!

Gentlemen.

This thread was meant to be professional, informative and, as usual, thought provoking.

I guess it worked? =))

Look. Zero out of three is pretty good if you are going to try again. :smiley:

Yes, try again… Please…? 8->

Exactly!

I have always measured my successes by how many times I tried rather than a subjective measurement of “successful outcome”.

Seems to be a safer and more achievable benchmark.



Meanwhile…

I figure we are getting closer to “Audiophile” friendly routers that will enable more WRT/Tomato features which will enhance our network Audio streaming.

I suspect that it is more inspired by the video crowd but I’ll take whatever we can get.



NB: call this a “soft” try. :smiley:

What’s this… Oh! We’re back to the original topic! I had to think about why _G was bringing up routers… I forgot that this thread really wasn’t about Wham! :-))

:open_mouth:

Routers? “We got no stinking routers, Gringo”

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OK Smartasses.



Eat This!



A mine shaft is 14’wide at the bottom and 10’wide at the top, 7’high.

if 1/2 the area is filled with water.How far up on the walls will the water go?

Zero. An area is a two dimensional form and cannot be “filled.”

Any other Smartasses out there? >:)

Ah, it could be a vertical shaft.

@gordon You mean volume don’t you? If a truncated cone is filled with 1/2 of the volume it can hold, how high would the water be?



The total capacity of your truncated cone would be 801.15 gallons. 1/2 that amount of water (is it water we are using?) = 400.6 gallons.



So, if we pour 400.6 gallons of water into the truncated cone, how high would it rise on the 7’ wall? Is this the question?



I get 3.5 feet. Is this correct?

If we assume that the difference from bottom to top is a consistent slope…

How did you come mathematically to the height.



Here’s one for Bill.

No looking it up!

What is Freddy Mercury’s real name? and where was he born?

@gordon Yes, I did assume a uniform slope. I also assumed the dimensions are interior diameters.

yes.

so, did you draw it or do it by math?

how?